SOLUTION: Wendy wants to build a frame of uniform width around the outside of her 21cm x 30cm photo but she can only afford 188cm² of wood for the frame. How wide will the frame be?
Question 1207376: Wendy wants to build a frame of uniform width around the outside of her 21cm x 30cm photo but she can only afford 188cm² of wood for the frame. How wide will the frame be? Found 4 solutions by josgarithmetic, Edwin McCravy, mccravyedwin, ikleyn:Answer by josgarithmetic(39613) (Show Source):
You can put this solution on YOUR website! You should draw the description and label the parts to help see.
w, the frame's uniform width; everything is rectangular shaped.
Whole area including the frame
Just the area of the frame ------------Simplify and solve this for w.
The frame is four rectangles, two are (30+x) by x and two are (21+x) by x.
So
That simplifies to:
Divide through by 2:
Solve by the quadratic formula:
Ignore the minus
About x = 1.726273692 cm = width of frame. Round off as you were told.
Edwin
The frame is the large rectangle minus the small rectangle.
Let x be the width of the frame, so the large rectangle is
30+2x by 21+2x and the small rectangle is 30 by 21 or 630.
So their difference must equal 188
That simplifies to:
Divide through by 2:
Solve by the quadratic formula:
Ignore the minus
About x = 1.726273692 cm = width of frame. Round off as you were told.
Edwin
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