SOLUTION: An astronaut standing on the surface of the moon throws a rock upward. The height of the rock is given by s=-2.7t^2+27t+6.3, where s is the height in metres and t is the time in se

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: An astronaut standing on the surface of the moon throws a rock upward. The height of the rock is given by s=-2.7t^2+27t+6.3, where s is the height in metres and t is the time in se      Log On


   

Question 120482: An astronaut standing on the surface of the moon throws a rock upward. The height of the rock is given by s=-2.7t^2+27t+6.3, where s is the height in metres and t is the time in seconds.What was the initial height of the rock?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Ans: s(0) = 6.3 meters
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Cheers,
Stan H.