SOLUTION: A soccer ball is kicked off the ground into the air and reaches its maximum height after 2 seconds. After 1 second the height of the ball is 15 feet off the ground. Write a quadrat

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: A soccer ball is kicked off the ground into the air and reaches its maximum height after 2 seconds. After 1 second the height of the ball is 15 feet off the ground. Write a quadrat      Log On


   



Question 1204485: A soccer ball is kicked off the ground into the air and reaches its maximum height after 2 seconds. After 1 second the height of the ball is 15 feet off the ground. Write a quadratic equation in vertex form to model this situation.
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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A soccer ball is kicked off the ground into the air and reaches its maximum height after 2 seconds.
After 1 second the height of the ball is 15 feet off the ground.
Write a quadratic equation in vertex form to model this situation.
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They want you find a quadratic equation in vertex form

    h(t) = a%2A%28t-t%5B0%5D%29%5E2+%2B+b.    (1)


It is the general quadratic equation in vertex form.



Now, the problem says that the ball reaches its maximum height after 2 seconds.

It means that the vertex is at  t= t%5B0%5D;  in other words, we should take t%5B0%5D = 2 (seconds).

So, I write  

    h(t) = a%2A%28t-2%29%5E2%2Bb.    (2)



Next, the problem says that After 1 second the height of the ball is 15 feet off the ground.

It means that I can write the last equation (2) in the form

    15 = a%2A%281-2%29%5E2%2Bb,    (3)

substituting 15 ft on the left side and replacing "t" by 1 second in the right side.

It gives me 

    15 = a + b.    (4)



Finally, the problem says that the ball is kicked off the ground.

It means that at t= 0 the height is zero: h = 0.

So, I substitute t= 0 and h= 0 into equation (2), and I get then

    0 = a%2A%280-2%29%5E2%2Bb,

or

    0 = 4a + b.    (5)


From (5), I have  b = -4a and substitute it into equation (4).  I get then

    15 = a + (-4a) = -3a;

hence

    a = -15%2F3,  or  a = -5.


Now I am ready to write the final equation from given data

    h(t) = -5%2A%28t-2%29%5E2+%2B+20.     <<<---=== highlight%28highlight%28ANSWER%29%29


      +---------------------------------------------+
      |    But now it is good time to discuss it.   |
      +---------------------------------------------+


First, having this equation in front of you, you can check that it SATISFIES the problem's conditions.


Second, it is good to re-write this equation in the standard form quadratic equation by opening parentheses

    h(t) = -5*t^2 + 10t + 0.    (6)


The zero (0) as a constant term is good, because it tells that the initial height is zero at t= 0.


Next, from the standard form (6) everybody, who is familiar with the subject, will say

    "HEY, they missed everything in the problem: the leading coefficient a= -5 says that the problem 
    should consider METERS instead of FEET.  For the Earth condition, a= -5 tells that the input numbers
    in the condition relate to METERS, not feet".


At this point, I complete my solution and my explanations.


From my post, you learn TWO THINGS:

    - first, you learn on HOW TO analyze and solve the problem, step-by-step.

    - second, you learn that the problem's formulation, as it is given in the post,
      is INCOORRECT and the word "feet" MUST BE replaced by the word "METERS" there.

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Solved and COMPLETED.

You should not be surprised by the error in the condition:
at this forum, every second post struggles having ERRORS, fatal or not-fatal.