SOLUTION: how would you graph the quadratic equation {{{y<-x^2+2x+1}}} and graph it as a parabala? I can graph {{{y>x^2-3}}} I know the -3 is the y intercept, but I am not quite sure how to

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: how would you graph the quadratic equation {{{y<-x^2+2x+1}}} and graph it as a parabala? I can graph {{{y>x^2-3}}} I know the -3 is the y intercept, but I am not quite sure how to       Log On


   

Question 117964: how would you graph the quadratic equation y%3C-x%5E2%2B2x%2B1 and graph it as a parabala? I can graph y%3Ex%5E2-3 I know the -3 is the y intercept, but I am not quite sure how to do this one. Could I factor to get my points?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
graph the quadratic equation y<-x^2+2x+1 and graph it as a parabola?
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You have the y-intercept as (0,1)
Find the x-intercepts:
-x^2+2x+1 = 0
x^2-2x-1 = 0
x = [2 +- sqrt(4-4*-1)]/2
x = [2 +- sqrt(8)]/2
x = [1 +- sqrt(2)]
x = 1+sqrt(2) or x = 1-sqrt(2)
x = 2.414 or x = -0.414
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C-x%5E2%2B2x%2B1%29
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Cheers,
Stan H.