SOLUTION: Grade 10 solve using the quadratic formula- The height of a ball thrown upward after a given amount of time is h = - 4.9t ^ 2 + 29.4t + 1 where h represents the height of the ball
Question 1178899: Grade 10 solve using the quadratic formula- The height of a ball thrown upward after a given amount of time is h = - 4.9t ^ 2 + 29.4t + 1 where h represents the height of the ball in metres , and t represents the time elapsed since the ball has been thrown . Determine the maximum height of the ball and at what time this occurs. What is the maximum height reached by the ball? How long is the ball above a height of 40 m ? When does the ball hit the ground? Found 2 solutions by Solver92311, ikleyn:Answer by Solver92311(821) (Show Source):
This is a quadratic function with a negative lead coefficient, therefore the graph of the function is a concave down parabola with a vertex at .
For a general quadratic in where , namely , the value of is given by . And
The ball hits the ground at the positive value of such that . Set the function equal to zero and solve using the quadratic formula for the positive root.
John
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