SOLUTION: Solve the following system of equations. \begin{array}{rl} \frac{3}{4} x + \frac{-1}{6} y & = \frac{1}{2} \\ \\ \frac{-1}{4} x + \frac{-1}{2} y & = 2 \end{array}

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Solve the following system of equations. \begin{array}{rl} \frac{3}{4} x + \frac{-1}{6} y & = \frac{1}{2} \\ \\ \frac{-1}{4} x + \frac{-1}{2} y & = 2 \end{array}      Log On


   

Question 1178249: Solve the following system of equations.
\begin{array}{rl}
\frac{3}{4} x + \frac{-1}{6} y & = \frac{1}{2} \\
\\
\frac{-1}{4} x + \frac{-1}{2} y & = 2
\end{array}
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52750) About Me  (Show Source):
You can put this solution on YOUR website!
.

U N R E A D A B L E



Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

%283%2F4%29x+%2B%28-1%2F6%29y++=+1%2F2...........eq.1
%28-1%2F4%29x+%2B+%28-1%2F2%29y++=+2.........eq.2
-----------------------------------
%283%2F4%29x+%2B%28-1%2F6%29y++=+1%2F2........both sides multiply by 12 to get rid of fraction
12%283%2F4%29x+-12%281%2F6%29y++=+12%2A%281%2F2%29
9x+-2y++=+6..........solve for x
x+++=2y%2F9%2B+6%2F9
x+++=2y%2F9%2B+2%2F3.........1a)


%28-1%2F4%29x+%2B+%28-1%2F2%29y++=+2.........eq.2.......both sides multiply by 4
-x++-2y++=+8...........solve for x
x=-8+-2y+.........2a)
from 1a) and 2a) we have
2y%2F9%2B+2%2F3=-8+-2y+.......solve for y
2y%2F9%2B2y+=-8+-2%2F3+
2y%2F9%2B18y%2F9+=-24%2F3+-2%2F3+
20y%2F9+=-26%2F3++
20y%2A3+=-26%2A9++....simplify
20y+=-26%2A3++
y+=-78%2F20+
y+=-39%2F10+

go to
x=-8+-2y+.........2a), substitute y
x=-8+-2%28-39%2F10%29+
x=-1%2F5+