Question 1178185: b Expand f(x) = (x − α) (x − β) and show that Δ = (α − β )^2
Hence show that the zeroes are x = α and x = β (as expected) and that the vertex is
(α + β)/2, −((α − β)/2)^2).
Answer by greenestamps(13195)   (Show Source):
You can put this solution on YOUR website!
You don't tell us what your "Δ" is, so we don't know what we/you are supposed to do with this....
If the function can be written as f(x) = (x-a)(x-b), then the zeros are a and b, and the symmetry of the graph tells us that the x coordinate of the vertex is (a+b)/2. Then the y value of the vertex is the function evaluated at x=(a+b)/2, which is the expression shown.
But because you haven't defined what "Δ" is, we don't know how to help you with your question.
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