Question 1176619: passing through (3,5)
Found 4 solutions by ewatrrr, MathLover1, ikleyn, josgarithmetic:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
Disregard comment. Tutors with same solution :)
Using the vertex form of a parabola,  where(h,k) is the vertex
Vertex (2,1)
y = a(x-2)^2 + 1
P(3,5)
5 = a+ 1
4= a
and Standard form:
y = 4(x^2 -4x + 4) + 1 = 4x^2 -16x + 16 + 1= 4x^2 -16x + 17
Wish You the Best in your Studies.
Answer by MathLover1(20849)  (Show Source):
Answer by ikleyn(52778)  (Show Source):
You can put this solution on YOUR website! .
Your post is FATALLY INCOMPLETE.
It missed the core of information.
As posted, the problem CAN NOT be solved.
Ignore the posts from two other ladies, since they (their posts) are IRRELEVANT.
Be more attentive next time, posting to this forum.
Be more attentive EVERY time, posting to this forum.
Answer by josgarithmetic(39617)  (Show Source):
|
|
|
