SOLUTION: How do I solve x^2+6x+4=0 in quadratc formula? I think this is how to slove x= -6+or-√6^2-4(x)(4)/2(x) -6+or-√36-4(x)(4)/2(x)
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Question 117555
:
How do I solve x^2+6x+4=0 in quadratc formula?
I think this is how to slove x= -6+or-√6^2-4(x)(4)/2(x)
-6+or-√36-4(x)(4)/2(x)
-6+or-√36-16/2(x)
-6+or-√20/2
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve
( notice
,
, and
)
Plug in a=1, b=6, and c=4
Square 6 to get 36
Multiply
to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this
solver
)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or
Now break up the fraction
or
Simplify
or
So these expressions approximate to
or
So our solutions are:
or
Notice when we graph
, we get:
when we use the root finder feature on a calculator, we find that
and
.So this verifies our answer