SOLUTION: Determine the equation of the quadratic given roots-1/3, -2/5
The answer must be in the form ax^2+bx+c=0
I got 15x^2+11x+6=0
I need help...I dont think this is right but when
Question 1171274: Determine the equation of the quadratic given roots-1/3, -2/5
The answer must be in the form ax^2+bx+c=0
I got 15x^2+11x+6=0
I need help...I dont think this is right but when the equation wasn't expanded and it had the brackets it made sense Found 2 solutions by ikleyn, ankor@dixie-net.com:Answer by ikleyn(52776) (Show Source):
An equation is
= 0
where each linear binomial factor is ASSOCIATED by the OBVIOUS way with the roots.
It is the same as
= 0
which is EQUIVALENT to
(3x+1)*(5x+2) = 0.
To get the standard form of a quadratic equation, make FOIL to get
15x^2 + 6x + 5x + 6 = 0,
Combining like terms, you get the FINAL ANSWER
15x^2 + 11x + 6 = 0.
You can put this solution on YOUR website! Determine the equation of the quadratic given roots-1/3, -2/5
The answer must be in the form ax^2+bx+c=0
:
We got
x = - 1/3
3x = -1
3x + 1 = 0
and
x = -2/5
5x = -2
5x + 2 = 0
FOIL (3x+1)(5x+2)
15x^2 + 6x + 5x + 2 = 0
15x^2 + 11x + 2 = 0 is what I get
