SOLUTION: Christian is planning to fence his vacant lot for a garden. The desired length of the lot is 2 meters longer than its width. What will be the possible dimensions of the rectangula

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Christian is planning to fence his vacant lot for a garden. The desired length of the lot is 2 meters longer than its width. What will be the possible dimensions of the rectangula      Log On


   



Question 1170497: Christian is planning to fence his vacant lot for a garden. The desired length of the lot is 2 meters longer than its width. What will be the possible dimensions of the rectangular garden if it should less than 8 sq. meters?
(Hint: Area of a rectangle is length x width)
With solutions please ;)

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

The desired length L of the lot is 2+meters longer than its width W.
L=W%2B2
area: A%3C8
A=L%2AW, so
L%2AW%3C8....substitute L
%28W%2B2%29%2AW%3C8
W%5E2%2B2W-8%3C0...factor
W%5E2-2W%2B4W-8%3C0
%28W%5E2-2W%29%2B%284W-8%29%3C0
W%28W-2%29%2B3%28W-2%29%3C0
%28W+-+2%29+%28W+%2B+4%29%3C0
solutions: need only positive solution
%28W+-+2%29+%3C0=>W++%3C2....first number less than 2 is
W+=1

find L=W%2B2
L=1%2B2
L=3