Question 116737: quadratic function in standard from of
(0,3) (1,-4) (2,-9)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! quadratic function in standard from of
(0,3) (1,-4) (2,-9)
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Form: ax^2+bx+c = y
Need to determine a,b,and c
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Substitute the x,y values of each point to get three equations:
0a + 0b + c = 3
1a + 1b + c = -4
4a + 2b + c = -9
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Using the TI-83 Matrix function I get:
a=1
b=-8
c=3
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EQUATION:
y = x^2-9x+3
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Cheers,
Stan H.
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