SOLUTION: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by h = −16t2 + 170t . How many seconds after the

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by h = −16t2 + 170t . How many seconds after the       Log On


   

Question 1154815: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by
h = −16t2 + 170t
. How many seconds after the launch will the rocket be 314 ft above the ground? Round to the nearest hundredth.
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

To get the answer, solve the quadratic equation


    -16t^2 + 170t = 314.


You will get 2 roots.


One root is the solution for the model moving up, while the other root is the solution for the model falling down.