SOLUTION: If a rock is thrown into the air on small planet with a velocity of 25 m/s, its height (in meters) after t seconds is given by y=25t−4.9t^2. Find the velocity in meters per seco

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Question 1146204: If a rock is thrown into the air on small planet with a velocity of 25 m/s, its height (in meters) after t seconds is given by y=25t−4.9t^2.
Find the velocity in meters per second of the rock when t=2.5. (Include units.)
Answer by Alan3354(69443) About Me  (Show Source):
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If a rock is thrown into the air on small planet with a velocity of 25 m/s, its height (in meters) after t seconds is given by y=25t−4.9t^2.
Find the velocity in meters per second of the rock when t=2.5. (Include units.)
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y=25t−4.9t^2
y' = 25 - 9.8t
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y', the 1st derivative of displacement, is the velocity.
Sub 2.5 for t.
---> m/s