SOLUTION: When an arrow is shot into the air, it’s height, h, in feet above the ground is given by the equation
h-16f^2+96t+5
Maximum height
How long will it take before the arrow sta
Question 1145361: When an arrow is shot into the air, it’s height, h, in feet above the ground is given by the equation
h-16f^2+96t+5
Maximum height
How long will it take before the arrow starts coming back down
To the nearest whole number, determine the value of Thor which the arrow hits the ground
Suppose the arrow hits a tree after 1.5 sec, stopping its path. How far up the tree would the arrow hit Found 2 solutions by richwmiller, ikleyn:Answer by richwmiller(17219) (Show Source):
1. Your post has a typo: instead of nonsensical expression
h-16f^2+96t+5
an equation
h = -16t^2+96t+5 (1)
must be present.
2. Formula (1) expresses the height h(t) as the quadratic function of "t".
For any quadratic function of the general form y = ax^2 + bx + c with negative leading coefficient "a" at x^2
it reaches its maximum value at x= .
In your case, a = -16, b= 96, therefore the height h(t) is maximal at
t = = = 3 seconds.
3. This model describes vertical movement of a projectile ONLY.
It does not describe its horizontal movement.
Therefore, the question related to a tree MAKES NO SENSE.
4. The post shows (clearly) that its author does not know the subject.
Such a post can not come from any textbook.
It means that the part related to a tree is created/"invented" by the author of the post.
My question is: if you don't know the subject, why (or for what purpose) do you try to create your own problem ?
