SOLUTION: A rectangular piece of metal is 25in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box. If th

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: A rectangular piece of metal is 25in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box. If th      Log On


   

Question 1145075: A rectangular piece of metal is 25in longer than it is wide. Squares with sides
5 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 930 in^3, what were the original dimensions of the piece of​ metal?
Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
Open Box dimensions:
height, 5 inches
length, w+25-2*5=w+15
width, w-10
volume, 930 cubic inches

5%28w%2B15%29%28w-10%29=930
Solve,...