SOLUTION: H=16t^2+181t+16 when y he height be 282 feet

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Question 1110717: H=16t^2+181t+16 when y he height be 282 feet
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
H=16t^2+181t+16
282=-16t^2+181t+16; note the editing, as it is usually -16t^2 for motion problems.
-16t^2+181t-266=0
quadratic formula
t=(-1/32)(-181+/- sqrt (181^2-4(-16)(-266)) sqrt term is 125.45
t=-55.55/-32=+1.73 sec
t=-306.45/-32=9.58 sec
graph%28300%2C300%2C-10%2C12%2C-100%2C600%2C-16x%5E2%2B181x%2B16%29
For the case where 282=+16t^2+181t+16
16t^2+181t-266=0
t=(1/32)(-181+/- sqrt (181^2+4(266)(16)) sqrt term is 192.4
t=11.4/32 (0.35) and minus 11.67.
graph%28300%2C300%2C-20%2C10%2C-1000%2C500%2C16x%5E2%2B181x-266%29