SOLUTION: Identify the axis of symmetry, create a suitable table of values and sketch the graph(including axis of symmetry). Y=x^2-5x+3
I would appreciate any help on this.
You can put this solution on YOUR website! Identify the axis of symmetry, create a suitable table of values and sketch the graph(including axis of symmetry).
Y=x^2-5x+3
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x^2-5x+3 = y
Complete the square on the x-terms and keep the equation balanced:
x^2-5x+(5/2)^2 = y-3 + (5/2)^2
Factor to get:
(x-(5/2))^2 = y+13/4
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Axis of symmetry: x = 5/2
Sketch as a vertical line passing thru all point where x = 5/2
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graph:
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Table: Y=x^2-5x+3
If x= 1 y=1-5+3 = -1
If x=2 y = 4-10+3= -3
If x=3 y = 9-15+3 -3
If x=4 y = 16-20+3 = -1
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Cheers,
Stan H.
You can put this solution on YOUR website!
Since , will be
Then
Axis of symmetry: …..=>……
Axis of Symmetry: ……or use decimal…
This is point through what the axis of symmetry passes. You need one more point to draw that line, and that point has to be a . Substitute for in the and find .
So, the vertex is: (,)
The graph will be a curve called a parabola
Here is the table:
x | y
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0 | 3
1 |-1
2.5 |-3.25
3 |-3
4 |-1
5 | 3
6 | 9
(