Question 1085950: For what negative value of k is there exactly one solution to this system of equations
y=2x^2+kx+6
y=-x+4 Found 2 solutions by rapture, ikleyn:Answer by rapture(86) (Show Source):
You can put this solution on YOUR website! Use the discriminant b^2 - 4ac.
a = 2, b = k, c = 6
Set discriminant to 0 and solve for k.
k^2 - 4(2)(6) = 0
k^2 - 8(6) = 0
k^2 - 48 = 0
k^2 = 48
sqrt{k^2} = sqrt{48}
k = sqrt{16}sqrt{3}
k = 4sqrt{3}, k = -4sqrt{3}
The negative k value is -4sqrt{3}.
