SOLUTION: 1. Solve the following quadratic equation: 2x^2-32=0 2. Given the function f\left(x\right)=x^2+12x, which c-value could be added to both sides of the equation when solving by

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: 1. Solve the following quadratic equation: 2x^2-32=0 2. Given the function f\left(x\right)=x^2+12x, which c-value could be added to both sides of the equation when solving by       Log On


   

Question 1085807: 1. Solve the following quadratic equation: 2x^2-32=0
2. Given the function f\left(x\right)=x^2+12x, which c-value could be added to both sides of the equation when solving by completing the square?
3. Use the quadratic formula to solve. 4x^2-3x-5=0
4. Solve : (x-1)^2-3=13
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

1. Solve the following quadratic equation:
2x%5E2-32=0
2x%5E2=32
x%5E2=32%2F2
x%5E2=16
x=+sqrt%2816%29
solutions:
x=4
x=-4

2. Given the function f%28x%29=x%5E2%2B12x, which c-value could be added to both sides of the equation when solving by completing the square?
f%28x%29%2Bc%5E2=%28x%5E2%2B12x%2Bc%5E2%29...since a=1 and 2ac=12=>c=6
f%28x%29%2B6%5E2=%28x%5E2%2B12x%2B6%5E2%29
f%28x%29%2B36=%28x%2B6%29%5E2


3. Use the quadratic formula to solve.
4x%5E2-3x-5=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%2A4%2A%28-5%29+%29%29%2F%282%2A4%29+
x+=+%283+%2B-+sqrt%28+9%2B80+%29%29%2F8+
x+=+%283+%2B-+sqrt%28+89+%29%29%2F8+
x+=+%283+%2B-+sqrt%28+89+%29%29%2F8+
exact solutions:
x+=+3%2F8+%2B+sqrt%28+89+%29%2F8+
x+=+3%2F8+-+sqrt%28+89+%29%2F8+

4. Solve :
%28x-1%29%5E2-3=13
%28x-1%29%5E2=13%2B3
%28x-1%29%5E2=16
%28x-1%29=+sqrt%2816%29
x=+sqrt%2816%29%2B1
solutions:
x=+4%2B1->x=5
x=+-4%2B1->x=-3