SOLUTION: Determine the quadratic equation with roots of -3/4 and 4/5

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Determine the quadratic equation with roots of -3/4 and 4/5      Log On


   

Question 1080024: Determine the quadratic equation with roots of -3/4 and 4/5
Found 3 solutions by ikleyn, amfagge92, MathTherapy:
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
It is 

%28x-%28-3%2F4%29%29%2A%28x-4%2F5%29 = 0,   


or, which is the same 


%28x%2B3%2F4%29%2A%28x-4%2F5%29 = 0,


or, if you want to avoid fractions,


(4x+3)*(5x-4) = 0.


You can open parentheses, if you want/if you need.


Answer by amfagge92(93) About Me  (Show Source):
You can put this solution on YOUR website!
For any quadratic equation
x^2-(SUM OF ROOTS)+(PRODUCT OF ROOTS)=0
x^2-x(-3/4+4/5)+(-3/4*4/5)=0
20x^2+x-12=0
is the equation.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the quadratic equation with roots of -3/4 and 4/5
Correct answer: highlight_green%28matrix%281%2C3%2C+20x%5E2+-+x+-+12%2C+%22=%22%2C+0%29%29, not: x%5E2+%2B+x+-+12+=+0