SOLUTION: P(x)=-2x^2+40x+320 Find the maximum profit of this quadratic equation Email:samiirockii@gmail.com

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Question 1079985: P(x)=-2x^2+40x+320
Find the maximum profit of this quadratic equation
Email:samiirockii@gmail.com
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
-2x%5E2%2B40x%2B320
x%5E2-20x-160
x%5E2-20x%2B100-100-160
%28x-10%29%5E2-260
Vertex at x=10

-

-2%2A10%5E2%2B40%2A10%2B320
-200%2B400%2B320
200%2B320
highlight%28520%29

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

P(x)=-2x^2+40x+320
Find the maximum profit of this quadratic equation
Email:samiirockii@gmail.com
P%28x%29+=+-+2x%5E2+%2B+40x+%2B+320

Maximum profit occurs where:  

Maximum profit, or: