Question 1079550: two parabolas are defined by y=x^2-x-12 and y=-0.5x^2+5x+100. what is the distance between their vertices ? Found 3 solutions by josgarithmetic, MathTherapy, Alan3354:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! Their vertices are ( 1/2, -47/4)( 1/2, -49/4 ) and (5, 225/2 ).
Distance between them with Distance Formula...
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You can put this solution on YOUR website! two parabolas are defined by y=x^2-x-12 and y=-0.5x^2+5x+100. what is the distance between their vertices ?
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y=x^2-x-12
Vertex at (0.5,-12.25)
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y=-0.5x^2+5x+100
Vertex at (5,112.5)
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distance = sqrt(4.5^2 + 124.75^2)
=~ 124.83 units
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