SOLUTION: What is the quadratic equation in standard form with set of points (0,-4) (1,0) (2,-2)
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Question 1075214
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What is the quadratic equation in standard form with set of points (0,-4) (1,0) (2,-2)
Answer by
Boreal(15235)
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ax^2+bx+c=y
x=0, y=-4 so c=-4
x=1 y=a+b-4=0
a+b=4
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x=-2
4a+2b-4=-2
4a+2b=2
a=4-b
16-4b+2b=2
-2b=-14
b=7
a=-3
-3x^2+7x-4=y