SOLUTION: Can you help me? Find all values of k for which the equation has one real solution. (k–1)t2+6t–9=0

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Question 1074098: Can you help me?
Find all values of k for which the equation has one real solution.
(k–1)t2+6t–9=0
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
(k–1)t2+6t–9=0
Quadratic?

(k–1)t^2+6t–9=0
%28k-1%29t%5E2%2B6t-9=0


6%5E2-4%2A%28k-1%29%2A%28-9%29=0, discriminant equals 0.
36%2B36%28k-1%29=0
1%2Bk-1=0
k=0