SOLUTION: A ball is thrown upwards. Its height is described by the equation h=-5t^2+20t where h is measured in meters and t is measured in seconds. a) Common factor h=-5t^2+20t b) How high

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Question 1073707: A ball is thrown upwards. Its height is described by the equation h=-5t^2+20t where h is measured in meters and t is measured in seconds.
a) Common factor h=-5t^2+20t
b) How high is the ball at 0 seconds? 1 Seconds? 2 Seconds?
c)Using the factored expression, find the time when the ball hits the ground.
d) Use your answer from c) to find the maximum height of the ball and when it occurs.
Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
h=-5t%28t-4%29
Common factor -5t.

(b)
Substitute 0, 1, 2, and evaluate each.

(c)
-5t%28t-4%29=0
t%28t-4%29=0
roots, 0 and 4.
The ball hits the ground after 4 seconds.

(d)
Maximum h happens at t=2 or 2 seconds.