SOLUTION: Given the functions h(x) = 12x + 3 and f(x) = x^2, which value of x makes h(x) = f(x)? a) 0 b) 1 c) 2 d) 3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Given the functions h(x) = 12x + 3 and f(x) = x^2, which value of x makes h(x) = f(x)? a) 0 b) 1 c) 2 d) 3      Log On


   

Question 1062561: Given the functions h(x) = 12x + 3 and f(x) = x^2, which value of x makes h(x) = f(x)?
a) 0
b) 1
c) 2
d) 3
Found 2 solutions by math_helper, MathTherapy:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Ordinarily, I'd recommend you set h(x) = f(x) and solve for x. However, there are only 4 choices given so it is easy just to plug in values:
x            h(x)=12x+3       f(x) = x^2
—            ——               ——
0             3                0
1             15               1
2             27               4
3             39               9
—

Too bad "none of the above" isn't a choice, as none of the given choices work.

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!

Given the functions h(x) = 12x + 3 and f(x) = x^2, which value of x makes h(x) = f(x)?
a) 0
b) 1
c) 2
d) 3
Set h(x) = f(x), which gives:

12x+%2B+3+=+x%5E2

0+=+x%5E2+-+12x+-+3

This trinomial CANNOT be factored so values for x will be IRRATIONAL and as the choices are RATIONAL, none of the given answers will work.