You can put this solution on YOUR website! x^2+6x-16
ax^2+bx+c
a=1
b=6
c=-16
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[-6+-(sqrt6^2-4*1*-15)]/(2*1)
[-6+-(36+60)]/2
(-6+9.8)/2
3.8/2=1.9 (0,1.9)
(-6-9.8)/2
-15.8/2=7.9 (0,7.9)
the two zeros
You can put this solution on YOUR website! .
I need a sample of how to solve x^2 + 6x - 16 = 0
I need a step by step process, as I do not understand
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There is a quadratic formula to solve any quadratic equation of the form
= .
This formula is
= .
It gives two solutions (two roots) (when you use the sign "+" at the square root) and (when you you use the sign "-" at the square root).
In your case a= 1, b= 6 and c= -16.
Apply the formula. You will get
= = = = .
So, the two roots are: = = = 2;
= = = -8.
The solutions of the given equations are 2 and -8.
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