SOLUTION: how do you solve 6x^2-19x-7=0 with the quadratic formula

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Question 1060218: how do you solve 6x^2-19x-7=0 with the quadratic formula
Found 2 solutions by josgarithmetic, Edwin McCravy:
Answer by josgarithmetic(39616) About Me  (Show Source):
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

6x%5E2-19x-7%22%22=%22%220

Compare to

Ax%5E2%2BBx%2BC%22%22=%22%220

A = 6, B = -19, C = -7

 x%22%22=%22%22%28-B+%2B-+sqrt%28B%5E2-4AC%29%29%2F%282A%29+

Substitute:

x%22%22=%22%22%28-%28-19%29+%2B-+sqrt%28%28-19%29%5E2-4%286%29%28-7%29%29%29%2F%282%286%29%29+ 

Simplify:

x%22%22=%22%22%2819+%2B-+sqrt%28361%2B169%29%29%2F12+ 

Simplify some more:

x%22%22=%22%22%2819+%2B-+sqrt%28529%29%29%2F12+ 

Simplify some more:

x%22%22=%22%22%2819+%2B-+23%29%2F12+

Use the +

x%22%22=%22%22%2819+%2B+23%29%2F12+

Siumplify:

x%22%22=%22%2242%2F12+

Reduce the fraction

x%22%22=%22%227%2F2+

That's one solution.

Use the -

x%22%22=%22%22%2819+-+23%29%2F12+

Siumplify:

x%22%22=%22%22%28-4%29%2F12+

Reduce the fraction

x%22%22=%22%22-1%2F3+

That's the other solution.
 
Edwin