SOLUTION: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

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Question 1045102: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
Answer by JoelSchwartz(130) About Me  (Show Source):
You can put this solution on YOUR website!
x=first consecutive number
y=second consecutive number
z=third consecutive number
y=x+1
z=x+2
xy=z^2-19
x(x+1)=(x+2)(x+2)-19
x^2+x=x^2+4x+4-19
15=3x
x=5
y=6
z=7