Question 1038212: How do i solve this
(x+2) squared =3(x+2)
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! (x+2)^2 = x^2 + 4x + 4
3*(x+2) = 3x + 6
your equation of (x+2)^2 = 3(x+2) becomes x^2 + 4x + 4 = 3x + 6
subtract 3x and 6 from both sides of the equation to get x^2 + 4x + 4 - 3x - 6 = 0
combine like terms to get x^2 + x - 2 = 0
factor this equation to get (x-1) * (x+2) = 0
solve for x to get -2 or x = 1.
those are your solutions.
to confirm they are applicable to the problem, replace x with 2 and then replace x with -1 in the original equations.
the original equation is (x+2)^2 = 3(x+2)
when x = -2, this equation becomes 0 = 0.
when x = 1, this equation becomes 9 = 9.
this confirms both solutions are correct.
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