SOLUTION: Airplane A travels 2400 km at a certain speed. Plane B travels 1800 km at a speed 50 km/h faster than Plane A in 2 hours less time. Find the speed of each plane.
Thank you
Question 1037668: Airplane A travels 2400 km at a certain speed. Plane B travels 1800 km at a speed 50 km/h faster than Plane A in 2 hours less time. Find the speed of each plane.
Thank you Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39617) (Show Source):
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Continue when that information does make sense.
Travel Rates Rule is RT=D to relate rate, time, distance.
Form this system of equations:
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Many algebraic steps needed in solving the system for r and t.
You would make a couple of different substitutions through the process.
Starting with the "1800" equation,
Use the first equation of the system to make substituion:
Now you will make another substitution using the "2400" equation either solved for r or solved for t...
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Airplane A travels 2400 km at a certain speed. Plane B travels 1800 km at a speed 50 km/h faster than Plane A in 2 hours less time. Find the speed of each plane.
Thank you
Let plane A’s speed be S
Then lane B’s speed is: S + 50
Time plane A takes: , while plane B takes:
We then get the following TIME equation:
2,400(S + 50) = 1,800S + 2S(S + 50) ------- Multiplying by LCD, S(S + 50)
(S - 400)(S + 150) = 0
S – 400 = 0 OR S + 150 = 0 (ignore)
S, or speed of plane A =
Speed of plane B: 400 + 50, or