SOLUTION: how many solutions does {y=4x+1, y=x^2+4} have? 0,1,2,or 3

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Question 1035398: how many solutions does {y=4x+1, y=x^2+4} have? 0,1,2,or 3
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
system%28y=4x%2B1%2C+y=x%5E2%2B4%29 

It's a line and a parabola, There could 0, 1, or 2 solutions.
3 is not possible

Let's graph the two equations:



Looks like there are two solutions.

We'll do it algebraically and see:

system%28y=4x%2B1%2C+y=x%5E2%2B4%29

Since both are solved for y, we can
set their right sides equal

4x%2B1=x%5E2%2B4

Get 0 on the left

0=x%5E2-4x%2B3

Switch sides:

x%5E2-4x%2B3=0

Factor:

%28x-3%29%28x-1%29=0

Use zero-factor principle:

x-3=0; x-1=0
  x=3; x=1

Now we get the corresponding y coordinates
by substituting each in y=4x%2B1

Substituting x=3

y=4x%2B1
y=4%283%29%2B1
y=12%2B1
y=13

So one solution is (x,y) = (3,13)

Substituting x=1

y=4x%2B1
y=4%281%29%2B1
y=4%2B1
y=5

So the other solution is (x,y) = (1,5)

It looks right from the graph:



Edwin