SOLUTION: A ball is thrown upward with an initial velocity of 64 feet/ sec. using h(t)= 64 t-16 t where h(t) is the height of the ball (feet) at any time second. find the height of the b

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Question 1030775: A ball is thrown upward with an initial velocity of 64 feet/ sec. using h(t)= 64 t-16 t where h(t) is the height of the ball (feet) at any time second.
find the height of the ball at time= 1 second?
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Using the formula:
h(t) = 64t - 16t
The height of the ball after 1 sec
will be:-
h(t) = 64(1) - 16(1)
h(t) = 64 - 16
h(t) = 48 feet
hope this helps :-)