SOLUTION: Solving using the quadratic formula. 7x(x+2)+5=3x(x+1) Do you first subtract the 3x^2 from 7x^2? I'm not 100% on how to work this through.

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Question 1027817: Solving using the quadratic formula.
7x(x+2)+5=3x(x+1)
Do you first subtract the 3x^2 from 7x^2? I'm not 100% on how to work this through.

Found 3 solutions by Cromlix, Theo, MathTherapy:
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
7x(x+2)+5=3x(x+1)
7x^2 + 14x + 5 = 3x^2 + 3x
7x^2 - 3x^2 + 14x - 3x + 5 + 0
4x^2 + 11x + 5 = 0
Solve using:-
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a = 4, b = 11 and c = 5
x+=+%28-11+%2B-+sqrt%28+11%5E2-4%2A4%2A5+%29%29%2F%282%2A4%29+
x+=+%28-11+%2B-+sqrt%28+121+-+80+%29%29%2F%288%29+
x+=+%28-11+%2B-+sqrt%28+41+%29%29%2F%288%29+
x+=+%28-11+%2B+sqrt%28+41+%29%29%2F%288%29+ : x+=+%28-11+-+sqrt%28+41+%29%29%2F%288%29+
x = -0.575 x = -2.175 (2 decimal places)
Hope this helps :-)

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
you want to get the quadratic equation into standard form first.

that form is ax^2 + bx + c = 0

a is the coefficient of the x^2 term.
b is the coefficient of the x term.
c is the constant term.

your equation is:

7x(x+2)+5=3x(x+1)

simplify by performing the operations indicated to get:

7x^2 + 14x = 3x^2 + 3x

not subtract all the terms on the right hand side from both sides of the equation to get:

7x^2 + 14x - 3x^2 - 3x = 0

now combine like terms to get:

4x^2 + 11x = 0

it is now in standard form of ax^2 + bx + c = 0

a = 4
b = 11
c = 0

now you can use the quadratic formula of x = (-b plus or minus sqrt(b^2-4ac)/(2a).

that will get you x = 0 or x = -22/8 which can be simplified to x = -11/4.

the graph of the resulting equation confirms that, as shown below:

$$$

the decimal equivalent of -11/4 is -2.75, as shown on the graph.


Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Solving using the quadratic formula.
7x(x+2)+5=3x(x+1)
Do you first subtract the 3x^2 from 7x^2? I'm not 100% on how to work this through.
7x(x + 2) + 5 = 3x(x + 1)
7x%5E2+%2B+14x+%2B+5+=+3x%5E2+%2B+3x -------- Distributing
7x%5E2+-+3x%5E2+%2B+14x+-+3x+%2B+5+=+0 ----- Subtracting 3x%5E2 from each side, as you surmised
4x%5E2+%2B+11x+%2B+5+=+0
Solve using the quadratic equation formula, as instructed.
a = 4
b = 11
c = 5