SOLUTION: 2x^2+8x-7=-2
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Question 1018613
:
2x^2+8x-7=-2
Answer by
Boreal(15235)
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2x^2+8x-7=-2
2x^2+8x-5=0
x=(1/4)*(-8+/- sqrt(64+40)=(1/4)*(-8+/-2 sqrt (26))=-2+/-(1/2)sqrt(26).
Numerically, this is about -4.55 and 0.55