SOLUTION: Use the method of completing the square to find the standard form of the quadratic function. f(x) = x^2 + 6x − 1 y= x= (x,y)=

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Use the method of completing the square to find the standard form of the quadratic function. f(x) = x^2 + 6x − 1 y= x= (x,y)=      Log On


   

Question 1003368: Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
y=
x=
(x,y)=
Found 3 solutions by lwsshak3, ikleyn, josgarithmetic:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
= x^2 + 6x-1=0
x^2 +6x=1
x^2+6x+9=1+9
(x+3)^2=10
(x+3=±√10
x=-3±√10


Answer by ikleyn(53833) About Me  (Show Source):
You can put this solution on YOUR website!
.
Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~


The problem's formulation in the post is absolutely illiterate from the Math point of view,

since the given function is JUST WRITTEN in the standard form.



Answer by josgarithmetic(39815) About Me  (Show Source):
You can put this solution on YOUR website!
In case you are looking for something else, you could use %286%2F2%29%5E2=3%5E2=9 to complete the square.

x%5E2%2B6x%2B9-1-9
x%5E2%2B6x%2B9-10
%28x%2B3%29%5E2-10
so function is f%28x%29=%28x%2B3%29%5E2-10.
This is not "Standard Form".