Tutors Answer Your Questions about Quadratic Equations (FREE)
Question 994539: Say whether the graph of the equation y=-x^2+4x-1 opens up, down, left, or right.Give the coordinates of the vertex and the equation of the axis of symmetry.Write your quadratic function in vertex form. Find the maximum or minimum value. Explain how you can determine this value.
Click here to see answer by josgarithmetic(39617)  |
Question 994539: Say whether the graph of the equation y=-x^2+4x-1 opens up, down, left, or right.Give the coordinates of the vertex and the equation of the axis of symmetry.Write your quadratic function in vertex form. Find the maximum or minimum value. Explain how you can determine this value.
Click here to see answer by MathTherapy(10552)  |
Question 995100: I am halfway through this problem and have been working on it/been stuck on it for quite some time. I think I got part a correct, but part b has stumped me. I've tried factoring it, but I get stuck. I figured that I probably need to do the quadratic formula to solve it, but I cant seem to figure it out with the instructions in my book.
The question is: If an archer shoots an arrow straight upward with an initial velocity of 160 ft/sec from a height of 8ft, then its height above ground in feet at time t in seconds is given by the function h(t) = -16t^2 + 160t + 8
a. What is the maximum height reached by the arrow?
I got 5 seconds. [Correct me if I'm wrong.]
0 = -32t + 160
-160 = -32t
-160/-32 = t
5 = t
b. How long does it take for the arrow to reach the ground?
So i get it down to:
0 = -16(t^2 + 10t -1/2)
...but don't know how to go from there without screwing it up.
Click here to see answer by josgarithmetic(39617) |
Question 995100: I am halfway through this problem and have been working on it/been stuck on it for quite some time. I think I got part a correct, but part b has stumped me. I've tried factoring it, but I get stuck. I figured that I probably need to do the quadratic formula to solve it, but I cant seem to figure it out with the instructions in my book.
The question is: If an archer shoots an arrow straight upward with an initial velocity of 160 ft/sec from a height of 8ft, then its height above ground in feet at time t in seconds is given by the function h(t) = -16t^2 + 160t + 8
a. What is the maximum height reached by the arrow?
I got 5 seconds. [Correct me if I'm wrong.]
0 = -32t + 160
-160 = -32t
-160/-32 = t
5 = t
b. How long does it take for the arrow to reach the ground?
So i get it down to:
0 = -16(t^2 + 10t -1/2)
...but don't know how to go from there without screwing it up.
Click here to see answer by MathTherapy(10552) |
Question 995296: Given a quadratic function g defined by g(x)=ax^2+bx+c , the solutions to the quadratic equation ax^2+bx+c=0 are x=−3.5±−4.5.
Determine if possible the axis of symmetry of g. If you do not have enough information write DNE.
Thanks in advance!:)
Click here to see answer by josgarithmetic(39617) |
Question 995296: Given a quadratic function g defined by g(x)=ax^2+bx+c , the solutions to the quadratic equation ax^2+bx+c=0 are x=−3.5±−4.5.
Determine if possible the axis of symmetry of g. If you do not have enough information write DNE.
Thanks in advance!:)
Click here to see answer by stanbon(75887) |
Question 995441: Given a quadratic function g defined by g(x)=ax2+bx+c , the solutions to the quadratic equation ax^2+bx+c=0 are x=−3.5±−4.5.
Determine if possible the axis of symmetry of g.
Please help and explain. Thanks in advance!
Click here to see answer by Fombitz(32388)  |
Question 995453: 1)Draw the parabola with a zero at (3,0) ,a vertex at (3,0) and a y intercept of (0,8)
2)Draw the parabola with a minimum value of 2, an axis of symmetry of 3, no zeros, and a y intercept of 8.
3)Draw the parabola with a y intercept of 4, an axis of symmetry of 0, and no zeros.
Click here to see answer by Boreal(15235)  |
Question 995565: Good Morning. I am trying to figure out how to complete the square for this problem but I am having no luck My problem is:
3x^2-13x+4=0. I know I have to divide each term by 3 which would give me:
x^2-13/3x+4/3=0. Then I subtract 4/3 on both sides to get x^2-13/3x=-4/3. I multiply -13/3xand 1/2 to get -13/6x then I square it to get 169/36 which I add to both sides of the equation.
x^2-13/3x+169/36=-4/3+169/36. Here is where I'm having a hard time and are looking for your help.
Click here to see answer by Timnewman(323)  |
Question 995565: Good Morning. I am trying to figure out how to complete the square for this problem but I am having no luck My problem is:
3x^2-13x+4=0. I know I have to divide each term by 3 which would give me:
x^2-13/3x+4/3=0. Then I subtract 4/3 on both sides to get x^2-13/3x=-4/3. I multiply -13/3xand 1/2 to get -13/6x then I square it to get 169/36 which I add to both sides of the equation.
x^2-13/3x+169/36=-4/3+169/36. Here is where I'm having a hard time and are looking for your help.
Click here to see answer by MathTherapy(10552) |
Question 995771: The formula A = 2πrh tells us the lateral surface area A of a cylinder with radius r and height h.
a) Solve the formula for radius, r.
b) Use the new version of the formula to find the radius of a can that has lateral surface area 301.44 square inches and height 12 inches. Use 3.14 as an approximation for π.
Click here to see answer by Alan3354(69443)  |
Question 995840: Explain why x^2+bx-c=0 must have one positive real and one negative real solution when b and c are real numbers and c>0 .
For what values of b will x^2+bx+1=0have real solutions? Clearly explain the reasoning you followed to reach your conclusion
Click here to see answer by josgarithmetic(39617) |
Question 996504: I am doing quadratic expression problems but I am stuck on this question:
-4=19x-5x^2
I am thinking that I should zero out the right side and and make a complete equation on the left. By doing this, do I then use the quadratic formula or do I complete the square to solve this problem. Am I on the right track?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 996504: I am doing quadratic expression problems but I am stuck on this question:
-4=19x-5x^2
I am thinking that I should zero out the right side and and make a complete equation on the left. By doing this, do I then use the quadratic formula or do I complete the square to solve this problem. Am I on the right track?
Click here to see answer by MathTherapy(10552) |
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