SOLUTION: Can you help me solve this problem? -4=19x-5x^2. Should I add 19x-5x^2 to both side then solve?

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Question 996527: Can you help me solve this problem?
-4=19x-5x^2. Should I add 19x-5x^2 to both side then solve?
Found 2 solutions by Timnewman, MathTherapy:
Answer by Timnewman(323) About Me  (Show Source):
You can put this solution on YOUR website!
No do not add it!!
This is a quadratic equation which can be written as;
5x²-19x+4=0
Then solve it by any method of your choice.
To me,i prefer factorization method.That is
(5x²-20x)+(x+4)=0
5x(x-4)+1(x+4)=0
(5x+1)(x+4)=0
Then,
x=-1/5 or x=-4
You can also solve it by formula method as follows
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 5x%5E2%2B-19x%2B4+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-19%29%5E2-4%2A5%2A4=281.

Discriminant d=281 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--19%2B-sqrt%28+281+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-19%29%2Bsqrt%28+281+%29%29%2F2%5C5+=+3.57630546142402
x%5B2%5D+=+%28-%28-19%29-sqrt%28+281+%29%29%2F2%5C5+=+0.223694538575979

Quadratic expression 5x%5E2%2B-19x%2B4 can be factored:
5x%5E2%2B-19x%2B4+=+5%28x-3.57630546142402%29%2A%28x-0.223694538575979%29
Again, the answer is: 3.57630546142402, 0.223694538575979. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+5%2Ax%5E2%2B-19%2Ax%2B4+%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Can you help me solve this problem?
-4=19x-5x^2. Should I add 19x-5x^2 to both side then solve? 
You should ADD 5x%5E2 to, but SUBTRACT 19x from both sides. This will give you: 5x^2 - 19x - 4 = 0

This can be factored to produce: highlight_green%28system%28x+=+4_OR%2Cx+=+%28-+1%2F5%29%29%29