SOLUTION: 6x^2+x-12=(ax+b)(cx+d)

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Question 989174: 6x^2+x-12=(ax+b)(cx+d)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
acx%5E2%2Bbcx%2Badx%2Bbd
acx%5E2%2B%28bc%2Bad%29x%2Bbd

system%28ac=6%2Cbc%2Bad=1%2Cbd=-12%29

A better way is to check separate trial combinations based on factorizations for 6 and factorizations for -12. 

(2x 2)(3x 6)
(2x 6)(3x 2)
(2x 3)(3x 4)
(2x 4)(3x 3)
(2x 1)(3x 12)
(2x 12)(3x 1)
but then there are six other combinations to check also!....