SOLUTION: Sara found the following equation: A= pi sqrt w/g i) if w=25 and g=16, Find A in terms of pi. ii) Sara now wants to use the formula to find w in a different situation. Rewr

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Sara found the following equation: A= pi sqrt w/g i) if w=25 and g=16, Find A in terms of pi. ii) Sara now wants to use the formula to find w in a different situation. Rewr      Log On


   

Question 986266: Sara found the following equation:
A= pi sqrt w/g
i) if w=25 and g=16, Find A in terms of pi.
ii) Sara now wants to use the formula to find w in a different situation. Rewrite the formula with w as the subject.
Found 2 solutions by stanbon, macston:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A= pi sqrt (w/g)
i) if w=25 and g=16, Find A in terms of pi.
A = pi*sqrt(25/16)
A = (5/4)pi
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ii) Sara now wants to use the formula to find w in a different situation. Rewrite the formula with w as the subject.
A = pi*sqrt(w/g)
A/pi = sqrt(w/g)
w/g = (A/pi)^2
w = g*(A/pi)^2
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Cheers,
Stan H.
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Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
A=%28pi%29sqrt%28w%2Fg%29
.
i) if w=25 and g=16, Find A in terms of pi.
.
A=%28pi%29sqrt%2825%2F16%29=%285%2F4%29%28pi%29
.
ii) Rewrite the formula with w as the subject.
.
A=%28pi%29sqrt%28w%2Fg%29
.
A%2Fpi=sqrt%28w%2Fg%29
.
%28A%2Fpi%29%5E2=w%2Fg
.
g%28A%2Fpi%29%5E2=w