SOLUTION: Find the value of k that makes the sum of the roots of 3x^2+18=(3k+2)x equal to 6

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Question 982691: Find the value of k that makes the sum of the roots of 3x^2+18=(3k+2)x equal to 6
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the sum of the roots are equal to -b%2Fa
the product of the roots are equal to c%2Fa
the standard form of the quadratic equation is
+ax%5E2+%2B+bx+%2B+c+=+0
your equation is:
3x%5E2+%2B+18+=+%283k%2B2%29x
subtract %283k%2B2%29x from both sides of the equation to get:
3x%5E2+-+%283k%2B2%29x+%2B+18+=+0
this equation is now in standard form of ax%5E2+%2B+bx+%2B+c=0 where:
a+=+3
b+=+-%283k%2B2%29
c+=+18
sum of the roots are -b%2Fa which becomes %283k%2B2%29%2F3
since sum of the roots is equal to 6, this means that %283k%2B2%29%2F3+=+6
solve for k
multiply both sides of this equation by 3 to get:
3k%2B2+=+18
subtract 2 from both sides of this equation to get:
3k+=+16
divide both sides of this equation by 3 to get:
k+=+16%2F3
that should be the value of +k
check if that works:

when k+=+16%2F3, 3k%2B2+=+3%2A16%2F3+%2B+2+=+18
then your equation 3x%5E2+%2B+18+=+%283k%2B2%29x becomes:
3x%5E2+%2B+18+=+18x
subtract 18x from both sides of this equation to get:
3x%5E2+-+18x+%2B+18+=+0
divide both sides of this equation by 3+to get:
x%5E2+-+6x+%2B+6+=+0
we can use the formula of sum of the roots =>+-b%2Fa to get 6%2F1+=+6
let's find the roots to see if the formula gave us the right answer.
the roots of this equation are:

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%2A1%2A6+%29%29%2F%282%2A1%29+
x+=+%286+%2B-+sqrt%28+36-24+%29%29%2F2+
x+=+%286+%2B-+sqrt%28+12+%29%29%2F2+

x+=+%286+%2B-+sqrt%28+4%2A3%29%29%2F2+

x+=+%28cross%286%293+%2B-+cross%282%29sqrt%28+3+%29%29%2Fcross%282%29+

x+=+%283+%2B-+sqrt%28+3+%29%29+
roots:
x+=+3+%2B+sqrt%28+3+%29+

x+=+3+-sqrt%28+3+%29+
and the sum is +%28+3+%2B+sqrt%28+3+%29%29%2B%283+-sqrt%28+3+%29%29=3%2Bsqrt%28+3+%29%2B3-sqrt%28+3+%29=6+