SOLUTION: solve the system: x+4y+2z=5 3x+7y+z=0 2x+5y+z=1 a. converting the augmented matrix into row-echelon form gives: 1 4 2 5 0 1 1 3 0 0 0 0 b. since the 3rd row corresponds

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: solve the system: x+4y+2z=5 3x+7y+z=0 2x+5y+z=1 a. converting the augmented matrix into row-echelon form gives: 1 4 2 5 0 1 1 3 0 0 0 0 b. since the 3rd row corresponds      Log On


   



Question 981205: solve the system:
x+4y+2z=5
3x+7y+z=0
2x+5y+z=1
a. converting the augmented matrix into row-echelon form gives:
1 4 2 5
0 1 1 3
0 0 0 0
b. since the 3rd row corresponds to an equation which is always true, we use the first 2 rows to solve for two of the variables in terms of the third. the first two rows correspond to the equation x+4y+2z=5 and y+____=____
c. solving the second equation for y gives: y=3-z
d. substitute the expression for in the first equation to get: x+4(3-z)+2z=____
e. solve this equation for x to get x=____

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
b.y%2Bz=3
c. True
d.x%2B12-4z%2B2z=5
e.x-2z=-7
x=2z-7