Question 978314: Thank you for answering my questions :)
The length of a rectangle is twice its width. If its length is decreased by 3m and its width is increased by 2m, the area of the resulting rectangle is 30m^2. Find the dimension.
In the previous it said its triangle but its rectangle... And i didnt notice it
Sorry for the typo error...
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The length of a rectangle is twice its width.
Let width be "x"::
Then length is "2x"::
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If its length is decreased by 3m and its width is increased by 2m, the area of the resulting rectangle is 30m^2. Find the dimension.
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New length:: 2x-3
New width:: x+2
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Equation::
(2x-3)(x+2) = 30
2x^2 + x - 6 = 30
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2x^2 + x - 36 = 0
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(x-4)(2x+9) = 0
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Positive solution::
x = 4m (original width)
2x = 8m (original length)
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Cheers,
Stan H.
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