SOLUTION: the full solution of 4a^2-147=a^2

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Question 975323: the full solution of 4a^2-147=a^2
Found 2 solutions by Fombitz, farohw:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4a%5E2-147=a%5E2
3a%5E2-147=0
a%5E2-49=0
%28a%2B7%29%28a-7%29=0
Two solutions:
a%2B7=0
a=-7
and
a-7=0
a=7

Answer by farohw(175) About Me  (Show Source):
You can put this solution on YOUR website!

4a%5E2+-+147+=+a%5E2

Isolate the variables on the left-side of the equation:

4a%5E2-a%5E2+=+147

Subtract:
4a%5E2-a%5E2+=+147 ---> 3a%5E2+=+147

Divide both sides by 3:

3a%5E2%2F3+=+147%2F3 ---> a%5E2+=+147%2F3 ---> a%5E2+=+49

a%5E2+=+49 --> a%5E2+-+49+=+0

Factor: %28a%2B7%29%28a-7%29+=+0 --> (a+7) = 0, (a-7) = 0

Solutions: a = -7, a = 7