SOLUTION: 3x-2x^2=7 (x+3)(x+4)=0

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Question 974325: 3x-2x^2=7
(x+3)(x+4)=0
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Rewrite first as 2x^2-3x+7=0
x=(1/4)[3 +/- sqrt(9-56) ;;;; sqrt(-47)
roots are (3/4) +/- i sqrt (47)
graph%28300%2C300%2C-10%2C15%2C-10%2C250%2C2x%5E2-3x%2B7%2Cx%5E2%2B7x%2B12%29
Not clear if these are supposed to be simultaneous equations.
x^2+7x+12=0 is the second
x^2+7x+12=2x^2-3x+7
-x^2+10x+5=x^2-10x-5
That solution (common to both equations) is when x=(1/2)[10+/- sqrt(100+20)]=(1/2)[10 +/- 2 sqrt(30]
Equal at 5 +/-5.47;; -0.47 and 10.47 would be approximate x-solutions.
Is this what you wanted?
equal at x=0.55 and 9.45