SOLUTION: How do I solve {{{ (x-1)/(x^2-2x-8)=(-2)/5 }}} ?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: How do I solve {{{ (x-1)/(x^2-2x-8)=(-2)/5 }}} ?      Log On


   

Question 973711: How do I solve +%28x-1%29%2F%28x%5E2-2x-8%29=%28-2%29%2F5+ ?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Ultimately you need to either isolate the variable, or put the equation into a form which you can handle with a standard finishing process. The other skills you already have. The simplest common denominator is 5%28x%5E2-2x-8%29; so multiply left and right members by this.


You should obtain this during the process:
2x%5E2%2Bx-17=0

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

How do I solve +%28x-1%29%2F%28x%5E2-2x-8%29=%28-2%29%2F5+ ?
%28x+-+1%29%2F%28x%5E2+-+2x+-+8%29+=+%28-+2%29%2F5, with system%28x+%3C%3E+4_or%2Cx+%3C%3E+-+2%29%29

Cross-multiply, collect like terms and you should get: 2x%5E2+%2B+x+-+21+=+0, which you can solve since it can be factored.