SOLUTION: find the coordinates of the x-intercepts given the quadratic function: y=x^2+2x-15

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Question 967847: find the coordinates of the x-intercepts given the quadratic function: y=x^2+2x-15

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2+3x-15 not factorable.

Roots or x-intercepts or ZEROS are
%28-3%2B-+sqrt%289%2B4%2A15%29%29%2F2.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

find the coordinates of the x-intercepts given the quadratic function: y=x^2+2x-15
x%5E2+%2B+2x+-+15+=+0

%28x+%2B+5%29%28x+-+3%29+=+0

x = - 5, or x = 3

Coordinate points of x-intercepts: (- 5, 0) and (3, 0)