SOLUTION: The width of a rectangle is 12 feet less than 3 times the length, and the area is 15 square feet. Part a: Write an equation that can be used to determine the length and width

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The width of a rectangle is 12 feet less than 3 times the length, and the area is 15 square feet. Part a: Write an equation that can be used to determine the length and width      Log On


   

Question 960938: The width of a rectangle is 12 feet less than 3 times the length, and the area is 15 square feet.

Part a: Write an equation that can be used to determine the length and width of the rectangle. Express your answer as a quadratic equation set equal to zero .
Part b: The length of the rectangle is ? feet.
Part c: The width of the rectangle is ? feet.
How do i solve this?
Thank you for yoour help.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28w=-12%2B3L%2C+wL=15%29;
Start substituting for w and solve for L. Use the now found L to finish solving for w.