Question 955517: A small rock sits on the edge of a tall building. A strong wind blows the rock off the edge. The distance, in feet, between the rock and the ground tseconds after the rock leaves the edge is given by d=−16t2−4t+472.
How many seconds after the rock leaves the edge is it 460feet from the ground?
How many seconds after the rock leaves the edge does it hit the ground?
If the answer is not an integer, enter it as a decimal. Round to the nearest hundredth, if needed.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A small rock sits on the edge of a tall building. A strong wind blows the rock off the edge. The distance, in feet, between the rock and the ground tseconds after the rock leaves the edge is given by d= -16t^2 - 4t + 472.
How many seconds after the rock leaves the edge is it 460 feet from the ground?
-16t^2 - 4t + 472 = 460
Solve for t.
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How many seconds after the rock leaves the edge does it hit the ground?
-16t^2 - 4t + 472 = 0
Solve for t.
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